AWG 35 voltage drop calculator
Voltage drop is current times the resistance of the round trip. For AWG 35 the resistance comes straight from the gauge definition and the conductor resistivity.
A
V
Voltage drop
563.101%
- Voltage lost in the cable
- 1295.1322 V
- Voltage at the load
- -1065.132 V
- Power lost as heat
- 25 902.64
- Resistance per metre
- 1.079 28 ohm/m
- Conductor area
- 0.015 973 7 mm2
- Longest run within 3% drop
- 0.16
Show the working
- Current = 20
- One-way run length = 30
- Supply voltage = 230
- System = 2
- Conductor = 1.724e-8
- Conductor temperature = 20
- diameter_mm = 0.127 * 92^((36 - (35)) / 39) = 0.142 612
- Conductor area = pi * 0.142 612^2 / 4 = 0.015 973 7
- Resistance per metre = 1.724e-8 / (0.015 973 7 * 1e-6) * (1 + 0.00393 * (20 - 20)) = 1.079 28
- Voltage lost in the cable = 2 * 20 * 1.079 28 * 30 = 1295.13
- Voltage drop = 1295.13 / 230 * 100 = 563.101
- Voltage at the load = 230 - 1295.13 = -1065.13
- Power lost as heat = 1295.13 * 20 = 25 902.6
- Longest run within 3% drop = 1.079 28 > 0 && 20 > 0 ? 230 * 0.03 / (2 * 20 * 1.079 28) : 0 = 0.159 829
Values are shown to six significant figures here; the arithmetic itself runs on exact fractions and is only rounded where a number is printed.
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The formula
- single phase or DC: drop = 2 x I x R per metre x one-way length
- three phase: drop = sqrt(3) x I x R per metre x one-way length
- R per metre = rho / area, corrected for temperature
The factor of two on a single-phase run is because the current goes out and comes back. A three-phase drop uses sqrt(3) because the return currents partly cancel.
This is resistive drop only. On long AC runs at high current, cable reactance adds to it.
Warm conductors have more resistance: at 70 degrees Celsius copper is about 20% more resistive than at 20.