AWG 35 wire size, resistance and weight calculator
AWG 35 is defined by the gauge formula, not by a table: the diameter is 0.127 mm times 92 raised to the power (36 - n) / 39. Everything else follows from that and the conductor resistivity.
A rough guide: 3 to 5 A/mm2 for chassis wiring, under 2 for long runs in conduit.
- Diameter
- 0.142 612
- Area in circular mils
- 0.031 524 4
- Resistance of that length
- 107.928 ohm
- Resistance per kilometre
- 1079.28 ohm/km
- Resistance per 1000 feet
- 328.964 ohm
- Weight of that length
- 0.014 312 4
- Current at the chosen density
- 0.06 A
- Turns per centimetre, close-wound
- 70.120
Show the working
- Length of wire = 100
- Conductor = 1.724e-8
- Conductor temperature = 20
- Conductor density = 8960
- Design current density = 4
- Diameter = 0.127 * 92^((36 - (35)) / 39) = 0.142 612
- diameter_in = 0.142 612 / 25.4 = 0.005 614 66
- Cross-sectional area = pi * 0.142 612^2 / 4 = 0.015 973 7
- Area in circular mils = 0.005 614 66^2 * 1000 = 0.031 524 4
- r_per_m_20 = 1.724e-8 / (0.015 973 7 * 1e-6) = 1.079 28
- r_per_m = 1.079 28 * (1 + 0.00393 * (20 - 20)) = 1.079 28
- Resistance of that length = 1.079 28 * 100 = 107.928
- Resistance per kilometre = 1.079 28 * 1000 = 1079.28
- Resistance per 1000 feet = 1.079 28 * 304.8 = 328.964
- Weight of that length = 0.015 973 7 * 1e-6 * 100 * 8960 = 0.014 312 4
- Current at the chosen density = 0.015 973 7 * 4 = 0.063 894 6
- Turns per centimetre, close-wound = 0.142 612 > 0 ? 10 / 0.142 612 : 0 = 70.1201
Values are shown to six significant figures here; the arithmetic itself runs on exact fractions and is only rounded where a number is printed.
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The formula
- diameter in mm = 0.127 x 92^((36 - n)/39)
- area = pi d^2 / 4
- resistance = rho x length / area
- temperature correction: R(T) = R(20) x (1 + 0.00393 (T - 20)) for copper
The gauge formula is exact: 36 AWG is 0.127 mm and 0000 AWG is 11.684 mm, with 39 steps between them in a geometric progression of ratio 92^(1/39).
The current figure is a design rule of thumb from current density, not an ampacity rating. Real ampacity depends on insulation temperature rating, bundling, ambient temperature and the wiring code in force.
Aluminium conductors of the same gauge carry about 61% of the current of copper for the same heating.
Frequently asked
What is the diameter of AWG 35 wire?
It follows from the gauge definition: 0.127 mm x 92^((36 - n)/39). The calculator shows the result in millimetres and inches.
Why does the wire gauge number go down as the wire gets thicker?
The number counts drawing operations. Each pass through a die makes the wire thinner and adds one to the gauge, so a high number means a thin wire.