Super 35 crop factor and field of view calculator
A Super 35 sensor measures 24.89 by 18.66 mm, a diagonal of 31.11 mm. Against the full-frame diagonal of 43.27 mm that is a crop factor of 1.391. The cinema standard, close to APS-C.
The diagonal divided by this gives the acceptable blur circle. 1500 is the usual modern figure.
- Full-frame equivalent focal length
- 48.68
- Equivalent aperture for depth of field
- 3.894
- Sensor diagonal
- 31.108
- Sensor area
- 464.45 mm2
- Full frame gathers this many times more light
- 1.860
- Horizontal field of view
- 39.148 degrees
- Vertical field of view
- 29.853 degrees
- Diagonal field of view
- 47.921 degrees
- Hyperfocal distance
- 21 131
- Depth of field
- 859
- Frame width at the subject
- 2.133
Show the working
- Focal length = 35
- Aperture f-number = 2.8
- Subject distance = 3
- Circle of confusion divisor = 1500
- sensor_w = 24.89 = 24.89
- sensor_h = 18.66 = 18.66
- Sensor diagonal = hypot(24.89, 18.66) = 31.108
- Crop factor = 31.108 > 0 ? 43.266615305567875 / 31.108 : 0 = 1.390 85
- Full-frame equivalent focal length = 35 * 1.390 85 = 48.6798
- Equivalent aperture for depth of field = 2.8 * 1.390 85 = 3.894 38
- Sensor area = 24.89 * 18.66 = 464.447
- Full frame gathers this many times more light = 464.447 > 0 ? 864 / 464.447 : 0 = 1.860 28
- Horizontal field of view = deg(2 * atan(24.89 / (2 * 35))) = 39.1479
- Vertical field of view = deg(2 * atan(18.66 / (2 * 35))) = 29.8526
- Diagonal field of view = deg(2 * atan(31.108 / (2 * 35))) = 47.9207
- coc = 31.108 / 1500 = 0.020 738 7
- Hyperfocal distance = 35^2 / (2.8 * 0.020 738 7) + 35 = 21 130.9
- near = 3*1000 * 21 130.9 / (21 130.9 + (3*1000 - 35)) = 2630.85
- far = 3*1000 < 21 130.9 ? 3*1000 * 21 130.9 / (21 130.9 - (3*1000 - 35)) : 1e9 = 3489.65
- Depth of field = 3489.65 >= 1e9 ? 1e9 : 3489.65 - 2630.85 = 858.805
- Frame width at the subject = 35 > 0 ? 3 * 24.89 / 35 : 0 = 2.133 43
Values are shown to six significant figures here; the arithmetic itself runs on exact fractions and is only rounded where a number is printed.
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The formula
- crop factor = full-frame diagonal / sensor diagonal
- field of view = 2 arctan(sensor dimension / 2 focal length)
- hyperfocal distance = f^2 / (N c) + f
- equivalent aperture = aperture x crop factor, for depth of field and total light
Crop factor changes the framing, not the lens. A 50 mm lens is always a 50 mm lens; it just sees a smaller rectangle.
Equivalent aperture matters for depth of field and total light gathered, not for exposure. An f/2.8 lens meters as f/2.8 on any format.
The circle of confusion is a judgement about acceptable sharpness at a viewing size, not a physical constant.
The cinema standard, close to APS-C.
Equivalent focal lengths on Super 35
| Lens | Full-frame equivalent |
|---|---|
| 12 mm | 16.7 mm |
| 16 mm | 22.3 mm |
| 24 mm | 33.4 mm |
| 35 mm | 48.7 mm |
| 50 mm | 69.5 mm |
| 85 mm | 118.2 mm |
| 135 mm | 187.8 mm |
| 200 mm | 278.2 mm |
Frequently asked
What is the crop factor of a Super 35 sensor?
1.391, calculated from its 31.11 mm diagonal against full frame at 43.27 mm.
Does a crop sensor make a lens longer?
No. The lens projects the same image; the smaller sensor simply records a smaller part of it, which looks like a longer lens.