Field of view calculator
Field of view is a right-triangle problem: the sensor is the opposite side and the focal length the adjacent one.
Horizontal field of view
54.432degrees
- Vertical field of view
- 37.849 degrees
- Diagonal field of view
- 63.440 degrees
- Frame width at that distance
- 5.143
- Frame height at that distance
- 3.429
- Area covered
- 17.633 m2
- Magnification
- 0.007 000
Show the working
- Sensor width = 36
- Sensor height = 24
- Focal length = 35
- Distance to subject = 5
- Horizontal field of view = deg(2 * atan(36 / (2 * 35))) = 54.4322
- Vertical field of view = deg(2 * atan(24 / (2 * 35))) = 37.8493
- diagonal = hypot(36, 24) = 43.2666
- Diagonal field of view = deg(2 * atan(43.2666 / (2 * 35))) = 63.44
- Frame width at that distance = 5 * 36 / 35 = 5.142 86
- Frame height at that distance = 5 * 24 / 35 = 3.428 57
- Area covered = 5.142 86 * 3.428 57 = 17.6327
- Magnification = 5 > 0 ? 35 / (5 * 1000) : 0 = 0.007
Values are shown to six significant figures here; the arithmetic itself runs on exact fractions and is only rounded where a number is printed.
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The formula
- angle of view = 2 arctan(sensor dimension / 2f)
- frame size = distance x sensor dimension / focal length
A 50 mm lens on full frame gives a 39.6 degree horizontal field, which is why it is called normal — it is close to the diagonal.