Convert btu per pound °fs to joule per kilogram kelvins
1 BTU/(lb·°F) = 4186.8 J/(kg·K) — exactly. Both units are defined against the SI, so this factor is a fraction, not an approximation.
How to convert btu per pound °fs to joule per kilogram kelvins
Multiply the number of btu per pound °fs by 4186.8 to get joule per kilogram kelvins.
The exact factor is 4186.8 — as a fraction, 20934/5.
BTU per pound °F: Numerically equal to cal/(g·°C) — the BTU and the calorie were built to line up this way.
BTU per pound °F to Joule per kilogram kelvin conversion table
| BTU per pound °Fs (BTU/(lb·°F)) | Joule per kilogram kelvins (J/(kg·K)) |
|---|---|
| 1 BTU/(lb·°F) | 4186.8 |
| 2 BTU/(lb·°F) | 8373.6 |
| 3 BTU/(lb·°F) | 12 560.4 |
| 5 BTU/(lb·°F) | 20 934 |
| 10 BTU/(lb·°F) | 41 868 |
| 20 BTU/(lb·°F) | 83 736 |
| 25 BTU/(lb·°F) | 104 670 |
| 50 BTU/(lb·°F) | 209 340 |
| 100 BTU/(lb·°F) | 418 680 |
| 250 BTU/(lb·°F) | 1 046 700 |
| 500 BTU/(lb·°F) | 2 093 400 |
| 1000 BTU/(lb·°F) | 4 186 800 |
Joule per kilogram kelvin to BTU per pound °F conversion table
| Joule per kilogram kelvins (J/(kg·K)) | BTU per pound °Fs (BTU/(lb·°F)) |
|---|---|
| 1 J/(kg·K) | 0.000 238 845 9 |
| 2 J/(kg·K) | 0.000 477 691 79 |
| 3 J/(kg·K) | 0.000 716 537 69 |
| 5 J/(kg·K) | 0.001 194 229 5 |
| 10 J/(kg·K) | 0.002 388 459 |
| 20 J/(kg·K) | 0.004 776 917 9 |
| 25 J/(kg·K) | 0.005 971 147 4 |
| 50 J/(kg·K) | 0.011 942 295 |
| 100 J/(kg·K) | 0.023 884 59 |
| 250 J/(kg·K) | 0.059 711 474 |
| 500 J/(kg·K) | 0.119 422 95 |
| 1000 J/(kg·K) | 0.238 845 9 |
Frequently asked
How many joule per kilogram kelvins are in a btu per pound °f?
One btu per pound °f equals 4186.8 joule per kilogram kelvins (BTU/(lb·°F) → J/(kg·K)). That figure is exact, not rounded.
How do you convert btu per pound °fs to joule per kilogram kelvins?
Multiply the number of btu per pound °fs by 4186.8 to get joule per kilogram kelvins.
What is 1 J/(kg·K) in btu per pound °fs?
One joule per kilogram kelvin is 0.0002388458966 btu per pound °fs.
What is 10 BTU/(lb·°F) in J/(kg·K)?
10 BTU/(lb·°F) = 41 868 J/(kg·K).
What exactly is a btu per pound °f?
Numerically equal to cal/(g·°C) — the BTU and the calorie were built to line up this way.