Convert joule per kilogram kelvins to btu per pound °fs

1 J/(kg·K) = 0.000238845896627 BTU/(lb·°F) — exactly. Both units are defined against the SI, so this factor is a fraction, not an approximation.

0.000 238 845 896 627BTU/(lb·°F)
≈ Rounded to 12 s.f. 1 J/(kg·K) ≈ 0.000 238 845 896 627 BTU/(lb·°F)
As a fraction: 5/20934
1 J/(kg·K) = 0.000238845896627 BTU/(lb·°F)

How to convert joule per kilogram kelvins to btu per pound °fs

Multiply the number of joule per kilogram kelvins by 0.000238845896627 to get btu per pound °fs.

BTU per pound °F: Numerically equal to cal/(g·°C) — the BTU and the calorie were built to line up this way.

Joule per kilogram kelvin to BTU per pound °F conversion table

Joule per kilogram kelvins (J/(kg·K)) BTU per pound °Fs (BTU/(lb·°F))
1 J/(kg·K) 0.000 238 845 9
2 J/(kg·K) 0.000 477 691 79
3 J/(kg·K) 0.000 716 537 69
5 J/(kg·K) 0.001 194 229 5
10 J/(kg·K) 0.002 388 459
20 J/(kg·K) 0.004 776 917 9
25 J/(kg·K) 0.005 971 147 4
50 J/(kg·K) 0.011 942 295
100 J/(kg·K) 0.023 884 59
250 J/(kg·K) 0.059 711 474
500 J/(kg·K) 0.119 422 95
1000 J/(kg·K) 0.238 845 9

BTU per pound °F to Joule per kilogram kelvin conversion table

BTU per pound °Fs (BTU/(lb·°F)) Joule per kilogram kelvins (J/(kg·K))
1 BTU/(lb·°F) 4186.8
2 BTU/(lb·°F) 8373.6
3 BTU/(lb·°F) 12 560.4
5 BTU/(lb·°F) 20 934
10 BTU/(lb·°F) 41 868
20 BTU/(lb·°F) 83 736
25 BTU/(lb·°F) 104 670
50 BTU/(lb·°F) 209 340
100 BTU/(lb·°F) 418 680
250 BTU/(lb·°F) 1 046 700
500 BTU/(lb·°F) 2 093 400
1000 BTU/(lb·°F) 4 186 800

Frequently asked

How many btu per pound °fs are in a joule per kilogram kelvin?

One joule per kilogram kelvin equals 0.0002388458966 btu per pound °fs (J/(kg·K) → BTU/(lb·°F)). That figure is exact, not rounded.

How do you convert joule per kilogram kelvins to btu per pound °fs?

Multiply the number of joule per kilogram kelvins by 0.000238845896627 to get btu per pound °fs.

What is 1 BTU/(lb·°F) in joule per kilogram kelvins?

One btu per pound °f is 4186.8 joule per kilogram kelvins.

What is 10 J/(kg·K) in BTU/(lb·°F)?

10 J/(kg·K) = 0.002 388 459 BTU/(lb·°F).

What exactly is a btu per pound °f?

Numerically equal to cal/(g·°C) — the BTU and the calorie were built to line up this way.

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