Super 16 crop factor and field of view calculator
A Super 16 sensor measures 12.52 by 7.41 mm, a diagonal of 14.55 mm. Against the full-frame diagonal of 43.27 mm that is a crop factor of 2.974.
The diagonal divided by this gives the acceptable blur circle. 1500 is the usual modern figure.
- Full-frame equivalent focal length
- 104.09
- Equivalent aperture for depth of field
- 8.327
- Sensor diagonal
- 14.548
- Sensor area
- 92.77 mm2
- Full frame gathers this many times more light
- 9.313
- Horizontal field of view
- 20.281 degrees
- Vertical field of view
- 12.085 degrees
- Diagonal field of view
- 23.482 degrees
- Hyperfocal distance
- 45 143
- Depth of field
- 396
- Frame width at the subject
- 1.073
Show the working
- Focal length = 35
- Aperture f-number = 2.8
- Subject distance = 3
- Circle of confusion divisor = 1500
- sensor_w = 12.52 = 12.52
- sensor_h = 7.41 = 7.41
- Sensor diagonal = hypot(12.52, 7.41) = 14.5485
- Crop factor = 14.5485 > 0 ? 43.266615305567875 / 14.5485 : 0 = 2.973 96
- Full-frame equivalent focal length = 35 * 2.973 96 = 104.089
- Equivalent aperture for depth of field = 2.8 * 2.973 96 = 8.327 09
- Sensor area = 12.52 * 7.41 = 92.7732
- Full frame gathers this many times more light = 92.7732 > 0 ? 864 / 92.7732 : 0 = 9.313 03
- Horizontal field of view = deg(2 * atan(12.52 / (2 * 35))) = 20.2811
- Vertical field of view = deg(2 * atan(7.41 / (2 * 35))) = 12.0853
- Diagonal field of view = deg(2 * atan(14.5485 / (2 * 35))) = 23.4819
- coc = 14.5485 / 1500 = 0.009 698 99
- Hyperfocal distance = 35^2 / (2.8 * 0.009 698 99) + 35 = 45 142.8
- near = 3*1000 * 45 142.8 / (45 142.8 + (3*1000 - 35)) = 2815.1
- far = 3*1000 < 45 142.8 ? 3*1000 * 45 142.8 / (45 142.8 - (3*1000 - 35)) : 1e9 = 3210.89
- Depth of field = 3210.89 >= 1e9 ? 1e9 : 3210.89 - 2815.1 = 395.79
- Frame width at the subject = 35 > 0 ? 3 * 12.52 / 35 : 0 = 1.073 14
Values are shown to six significant figures here; the arithmetic itself runs on exact fractions and is only rounded where a number is printed.
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The formula
- crop factor = full-frame diagonal / sensor diagonal
- field of view = 2 arctan(sensor dimension / 2 focal length)
- hyperfocal distance = f^2 / (N c) + f
- equivalent aperture = aperture x crop factor, for depth of field and total light
Crop factor changes the framing, not the lens. A 50 mm lens is always a 50 mm lens; it just sees a smaller rectangle.
Equivalent aperture matters for depth of field and total light gathered, not for exposure. An f/2.8 lens meters as f/2.8 on any format.
The circle of confusion is a judgement about acceptable sharpness at a viewing size, not a physical constant.
Equivalent focal lengths on Super 16
| Lens | Full-frame equivalent |
|---|---|
| 12 mm | 35.7 mm |
| 16 mm | 47.6 mm |
| 24 mm | 71.4 mm |
| 35 mm | 104.1 mm |
| 50 mm | 148.7 mm |
| 85 mm | 252.8 mm |
| 135 mm | 401.5 mm |
| 200 mm | 594.8 mm |
Frequently asked
What is the crop factor of a Super 16 sensor?
2.974, calculated from its 14.55 mm diagonal against full frame at 43.27 mm.
Does a crop sensor make a lens longer?
No. The lens projects the same image; the smaller sensor simply records a smaller part of it, which looks like a longer lens.